lewisneo

14

hace 5 años

Hi Barbesi, thank you very much for responding. Now excuse my little knowledge, can you please tell me what ESR is? Now I take the opportunity to ask, I am measuring the diodes and one in particular the 31DQ10 gives me a measurement of 226 ohm, the diode takes it out of the board and I have the multimeter on the diode scale, is that measurement of 226ohm correct? Is the diode in good condition? because all the other diodes mark me above 500ohm.

barbesi

709

hace 5 años

The diode is good, the ESR is the internal impedance of either a capacitor or an inductor that at a signal or voltage varying over time, that is to say alternating voltage, their internal resistance varies at a certain frequency, when that impedance rises your capacitor gives problems remember that the impedance of a capacitor is
1 / (wc) or is equal to 1 / (2 * pi * f * C) which means that if the frequency is high it will have a high impedance at a high frequency and this is to the manufacturing materials of the Therefore, it is important that the ESR is very low.

barbesi

709

hace 5 años

This type of failure is very common in electronic equipment, remember that it is not necessary that the condenser is inflated, it can visually look good but your ESR may be bad. Another thing do not forget to evaluate the proposals of solutions since this motivates us to continue raising solutions, Greetings.

lewisneo

14

hace 5 años

Greetings dear Barbesi, thank you very much for commenting, today I was investigating what you indicated to me, the topic of the ESR, so I need a capacimeter or an ESR meter, which I do not have, how should I proceed? Thank you very much in advance. By the way I don't know where I should evaluate the proposals for solutions I remind you that I am new to the forum,

barbesi

709

hace 5 años

To assess the answers:
Below each answer are the options, choose one for that answer and press "Rate" on each one.
If the answer does not help you at all, you value as Comment
If I help you solve your problem you value it Assistance to the Solution
If it really was the solution, you value it as a Solution
Help us improve the forums by correctly assessing the answers

barbesi

709

hace 5 años

You need an ESR meter or quality factor. The capacimeter measures you only the capacitance but this is not enough. The advantage of ESR is that you can measure it without needing to remove the component.

lewisneo

14

hace 5 años

Greetings, under each answer I only see a garbage basket to erase it and if I want to like it, it tells me that I cannot do it, and checking to try to assess the answers, press the accepted solution button,
I've seen several videos of how to make an ESR

lewisneo

14

hace 5 años

I finally found the source scheme, I only have the power fail voltage of the CP3902 connector, and 6V after the diode bridge and the transformer primary voltages, I have no signal on the power on H pin.
Should I bypass the fountain? If so, which pins should I bunge?

barbesi

709

hace 5 años

To discard the main disconnect it from the source, then make a bridge between standby power on and power inverter, place the power and must turn on the source, check all the voltages and must turn on the lamps, if all this does your problem is in the main Some TV with just disconnecting the main turns on the lamps and starts the source, in others there is that identify the ON / OFF a 10K resistor is placed between ON / OFF and VCC, that power to turn on, check and comment. Greetings.

lewisneo

14

hace 5 años

Thank you very much, in the question I left a link where the complete loops of the source are, could you tell me which of the pins that are in the plane should I bridge? This source has two connectors of 15 and another of 14 pins that go to the main, and another of 14 pins that goes to the inverter. and I don't want to bridge in a wrong way.