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LCD TVs - LED

SAMSUNG LCD screen - UN50FH5303F smd backlight resistors.

zaidramirez
hace 5 años
hace 5 años
Hello, good day, afternoon or evening, will someone by any chance have the value of these resistances? I describe the problem. The screen is a Samsung LCD model UN50FH5303F the problem is that I arrive without brightness on the screen, when checking the strips all bring LEDs in short or burned, only turn on some, and there are also 4 smd resistors damaged which are not distinguished well the value, the resistances are: R 9151 R 9152 R 9153 R 9157 These resistors are at the voltage output to the backlight, before them there are 320V stable with and without the connected strips, after the resistors and with the connected strips there are 120V to 150V variants, visible on the strips that just light up ( and replace them), with the strips disconnected there are 230V that vary more or less. If anyone can help me with those values, in advance, thank you. Look for information or the diagram without success. Attached photos. IMG_20191217_034206256.jpg [381.13kb] IMG_20191217_034150395.jpg [572.50kb] IMG_20191217_034115645.jpg [407.33kb] IMG_20191217_034123779.jpg [397.46kb] IMG_20191217_034129749.jpg [584.44kb] Thank you.
first
first
236
hace 5 años

I leave you a link within this same website, which seems to lead to a scheme that uses this source, I hope it is worth it: https://www.yoreparo.com/es/tv/televisores/lcd/led/preguntas/1465455/fuente -samsung-bn44-00668a

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eov47
eov47
665
hace 5 años
hace 5 años
Hi, I don't have the diagram, but from what you can see, they are low value R (3.9 - 4.7 ohm) in parallel with each other and in series with the LEDs. Therefore its value is not critical, you could put 4 smd of 4.7 ohms or a common of 1.5 ohms 1w. (approx.) What is advisable is to lower the voltage on the LEDs (usually factory exceeded). According to the circuit, it is done by increasing the value (if there are several in parallel, taking out half) of R that has "S" of the mosfet to mace or varying resist. from the "I-SEN" socket of the CI. The voltage is obtained by adding the total number of LEDs that are in series (the ideal is to leave it at 1% less) lowers the brightness a little, but it ensures you do not burn again. Ex .: 45 leds of 3v. = 135 v. maximum - ideal (1% less) = 133.65 v. . Cheers
zaidramirez
hace 5 años

Hi, thanks for the help.

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