Thanks for trying to help me, I never said that I tried the bimetallic at room temperature to activate it with ice in a glass of water and there it gave me continuity, what I said was to remove the bimetallic and bridge the cables where it goes, and to test the resistance and in the amperage I gave as reading 0.08 with the Bimetallic ON the amperage falls to 0.04 to 0.05 and what it manages to defrost is half, and bimetallic change as 6 the one I found is from L47-22f, install one of L45-22f , then remove it install the same capacity as it had and still the same also probe with l60-40f and L50 and nothing
Hi MultiTec, I just tried to explain how it works and how to make the measurements of the bimetal, in no case and said another thing, yes I warn you that the test with a glass with cold water, that is not correct, because the bimetal does not It is a simple switch, this element must be measured by operating on the equipment itself and I have already told you the correct way, because not only must the circuit open and close, but the time necessary for the resistance to do its part must also be activated. . A bimetal can close the circuit at 0 degrees Celsius, and it does not support 5 minutes activated later.
I don't know where he places the bimetal, in the evaporator coil of the equipment, because an L60 in LG, works perfectly, there are those who prefer the L50, but for me, he L60, obviously in good condition, allows to make a more perfect thaw, because it keeps to defrost resistance, a minimum of time greater than the L50. If you place the L60, on the upper left end of the evaporator coil, the bimetal receives less heat from the resistor and supports longer operating time. Change the scale of the ammeter to that of 20 amps, as a resistance of 0.92 ohm would be more than 1 amp.
Hello, I'm glad for you, highlighting, that something was not doing well with the measurements and scale used in the multimeter, because yes the previous resistance had a reading, 0.92 ohm, obviously it should work, turning red as it says and should as I already told you in my comment, consume more than 1 amp. S @ lu2