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Building

Calculate iron width for grid

Pablo Vasquez
hace 5 años
hace 5 años
Hello! I need to size the iron I need to assemble a 1m x 0.40m grid and support at least 20tn or maybe a little more (trucks will pass). And if you can tell me how the calculation method is much better so next I will do it. Thank you!
Pablo Vasquez
hace 5 años

It would be a concrete well and a tray folded in 3/16 "sheet (this part is already made for me to make the grid only) so that the grid is supported. The grid was intended to make it of sheet of a thickness of 6mm or more less, if I put the profile in the middle, will that thickness be enough?

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agustinp
agustinp
2.247
hace 5 años

Being a sheet has no load-resistant module. It makes a simple test. He will grab a school ruler, take it from the tips and ask another person to force it in the middle. Look at the behavior when it is vertical (impossible to deform it). However, if you put it horizontal it bends almost effortlessly. Therefore, a 6mm sheet can be resistant to compression or traction, but not to internal stress. That's why I commented an easy solution to the use of planchuela profiles vertically, as if they were the beams of a roof and the sheet metal slab

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agustinp
agustinp
2.247
hace 5 años

You put the sheet or any type of material, but with reinforcements below, if they are embedded in the concrete much better. This will reinforce the sheet without using a lot of material, at most you will spend a 1 1/2 "x 1/4" flat iron bar that can leave you less than 400 Argentine pesos

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agustinp
agustinp
2.247
hace 5 años
hace 5 años
Pablo, it's really very cumbersome to explain The method is very long. Not only do you need to know the load in this specific case of 20 metric tons, but you also need to see with great accuracy the issue of links and supports. If you want to do well you need a well done calculation, it really does not give to write 10 minutes on how to draw the diagram of shear stresses, moments, inertia, etc. etc. In addition, it is very unlikely that they really support 20 metric tons. Think that a truck can weigh that in net (as very exaggerated creeria) that must be seen what reaction has in each link, in this case the wheels, which can go down to half I would try to make a grid with angles, the cantilever part (that is to say where it does not support and receives the entire load) to put some slab profiles vertically where its moment of inertia is much greater, of a measure at least 1/4 "x 1 1/2". If it bends, well, try again. It is not for much, it is a little afternoon of laburo only
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