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Electronics and Circuit Design

How to connect 30 leds of 3v / 3.6, 700 ma in series and direct to 220

edu2006

hace 5 años

Hello friends, I am trying to make the calculations to connect 30 and maybe 60 full spectrum LEDs that are 3 / 36V, 700 milliamper or 3W directly at 220v AC and there are so many contradictions that I don't know which one is the best of all, obviously I speak of resistance in its value and POWER. if anyone can contribute any ideas thank you very much

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Salvador perez maximo

28.737

hace 5 años

Hello good afternoon that is not possible man receives best regards ok friend.

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Salvador perez maximo

28.737

hace 5 años

Hello, I give you this as a solution, the LEDs are going to direct current, the alternation is not useful and less that voltage ok friend.

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Yonny Diaz

2.185

hace 5 años



hace 5 años

Hello, you can do it by placing a bridge rectifier soon or made with diodes 1n4007 or similar, to take advantage of the two half cycles of the alternating current and a resistor of 5.5 K of at least 3 watts of dissipation to avoid problems ... Credit that does not have to work with as many as 60 the limit would be about 50 since if you connect many more, the sum of the voltages of each led will exceed the network voltage and the LEDs will not turn on ... Greetings ....

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edu2006

hace 5 años

Hi Jonny, I see that you understood my doubt, but I take the opportunity to clarify here for others, that I may express myself wrong in my query. Since I have to go a rectifier bridge from alternating to continuous for any LED, but my query is in the power of the resistance, you tell me 3W and my calculation gives me something else. You can also go a capacitor with a resistor or two resistors or three. With 30 leds at 220v it is enough knowing how to limit the current. 3 / 3,6v, 3W, 700 Ma LEDs

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Yonny Diaz

2.185

hace 5 años

Hello again Edu ... For trainers maybe you can dispel doubts here: http://elrincondeloscircuitos.blogspot.com.br/2011/01/leds-220v.html
As for the calculations, Here: https: //pt.scribd.com/doc/144575614/Como-Conectar-Muchos-Leds-a-220V

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Yonny Diaz

2.185

hace 5 años

We have 30 white LEDs of 3.6V drop in each. To obtain a good light we opted for an approximate current of 20mA. The resulting formula will be:
As the voltage drop in the rectifier diodes is very low compared to that of the LEDs, we may not consider it to simplify the formula. Now we calculate the resistance power:
R = (Vac - (Vled * NumLeds)) / I
R = (220V - (3.6V * 30)) / 20mA
R = 5.600 ohm (5.6K)
P = I2 * R
P = 20mA * 20mA * 5,600 ohm
P = 2.24 Watt

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