48v 20A power supply
good .
what you burn if you try to get 20A, it burns with less.
you should look for a PWM regulator circuit for those magnitude of current.
I do not think so. This transistor can withstand 64 amps at 100 degrees and can dissipate 230 watts maximum.
If we use 2 in parallel as indicated, there will be no problem in the case of lower voltages.
Keep in mind that the applicant requests to regulate 48 volts and in that case the voltage drop in the transistor is only 2 volts that multiplied by the 20 amps that he wants to take out are only 40 watts of dissipated power.
50v-48v = 2v.
Of course, it is essential to place a heatsink as directed.
good .
that is a shunt resistor, converts the current into voltage and polarizes the DB137, so that when the 0.7V of the drop in this resistance is reached, the transistor is activated, at that moment it takes the mosfet gate to GB, which you must pay it and avoid the current conduction, in reality it is not possible to turn off only the output current and the voltage in the R of 0.4 ohm are limited, it is close to 0.7V, but it does not fully activate the transistor and therefore the mosfet is not completely turned off.
Thank you Sergiouasd for your comment. I'm interested in the circuit since I'm looking for a similar source with high current. Although I understand electronics a bit, it is not so much to get involved in the analysis of some designs since my training is electricity.
I want to incorporate a voltmeter and a perimeter. What I fear of the temperature generated by the resistance with a load at a voltage of 24 and current of 10 Amp. That implies a power of 240W. I don't know if in the local market I would find that resistance resistance. How important is the transistor designed on resistance?
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