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Emergency lights

Repair 6v 4ah Rechargeable Halogen Flashlight

gera_central
hace 5 años
hace 5 años
Good evening, my name is Gerardo, this is my second post in the forum and I need help reconnecting a circuit of a Halogena lamp lantern, which has a 6v 4 ah battery. It comes with mains charger and car cigarette lighter plug charger included. The issue is that I do not know how to connect the circuit to charge the battery and in turn the halogen lamp is connected correctly. To guide them, I tell you that: The load jack has a resistance of 10 Ohm in the positive, then in series a diode 1n4007, but I don't know where it is connected. After the same jack the negative comes out, but I don't know how to rebuild the entire battery charging system. I attached an image of the flashlight that is the same but the one I have is from another brand. [Img] https://www.amazon.es/millones-Potencia-hal%C3%B3gena-Linterna-Cargadores/dp/B01N3O7U0T/ ref = sr_1_8? keywords = flashlight + halogen & qid = 1559431678 & s = gateway & sr = 8-8 [/img] Of course I would appreciate the help provided.
JoseOrtiz
JoseOrtiz
1.274
hace 5 años

The image was not uploaded, it shows the wiring area or circuit where you have doubts

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gera_central
hace 5 años

Good night Jose, there I uploaded the image, tomorrow I will take a picture of my unarmed flashlight and the circuit and upload it. Thanks for the prompt response.

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axel stone
hace 5 años

Hi, I have a friend who has this same lamp and has a 12V RELAY and a swichet and a diode with a capacitor, let me paint an improvised circuit to see how the internal connection is.

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axel stone
hace 5 años
hace 5 años
[url=/ver-adjunto/aHR0cHM6Ly9hZGp1bnRvcy55b3JlcGFyby5jb20vZGVmYXVsdC8wMDA0LzgxL2xpbnRlcm5hLTI5NjUuanBn] [img] /js/atta.png/chta.atch/chta.atch/chta.png/bta.png/bta.png.wind.png/bta.png.png.png/bta.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png.png. HERE IS THE FLASHLIGHT CIRCUIT INTERNALLY That is not the original circuit, it is CLEARLY modified, the original has a 12v relay, a diode and a small electrolytic capacitor in a small platelet that I do not see there, that circuit that has original is made so that when it is charging the battery to the give the swhiche DOES NOT TURN ON and only devote to charging the battery, check the circuit that I left in the previous post and I recommend using it to leave it original, now if you want to use those components there I will arm you another MORE ELABORATED circuit and simple WITH WHAT I OBSERVE THERE: CIRCUIT LINK: [url=/ver-adjunto/aHR0cHM6Ly9hZGp1bnRvcy55b3JlcGFyby5jb20vZGVmYXVsdC8wMDA0LzgyL2QzLTg3NjM4LmpwZw==] [img] /js/atta/plung.b25.png/bng.b25/ptang.png/bta.png/bta.png/bng/gb.png/bta.png/bta.png/bta.png/bta.png/bta.png/bta.png/bta.png/bta.png/bta.png/gta.png/gta.png/gta.png/gta.png/gta.png/gta.png/bta.png/gta.png/gta.png/bta.png/gta.png/gta.png/gta.png/gta.png/gta.png Cheers
gera_central
hace 5 años

Thanks Axel, I am going to make the circuit that you recommend for me to be original. I thank you
regards

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axel stone
hace 5 años

d1, d2, d3 can be 1n4001 or 1n4007 R1 = 2.2 ohms at 10 ohms per 1watt of power, the rest you already have

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gera_central
hace 5 años

give it great thank you

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axel stone
hace 5 años

you can do any of the 2, now if you do it as the best original, the same will both work for you, and nothing was a placard gera_central

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gera_central
hace 5 años
hace 5 años
Hi Axel, thanks for answering, I attached some pictures of how the circuit of this flashlight is. [Img] https://adjuntos.yoreparo.com/imagen_post/0004/82/9aa04314a2c109d5776a51b036f3e1e09b31f103.jpeg [/img]
axel stone
hace 5 años

check in my previous post there I left a circuit, not the first but the second, the first is how this lamp ORIGINALLY comes from, it is second is the diagram that I propose that you arm this lamp by the way R1 can be a resistance between 2.2 ohms at 10 ohms of the same watts you have in the figure, which I estimate is 1w of power

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